0.04^(3-sqrt(3x+2))=25*5^(sqrt(3x+2))
Please help ASAP
0.04^(3-√(3x+2))=25*5^√(3x+2)
Recall that .04 = 1/25 = 5^-2, and 25=5^2
So, now you have
5^(-2(3-√(3x+2)))=5^(2+√(3x+2))
Now take logs base 5 of both sides, and you have
-2(3-√(3x+2)) = 2+√(3x+2)
-6 + 2√(3x+2) = 2 + √(3x+2)
√(3x+2) = 8
3x+2 = 64
3x = 62
x = 62/3