There was a total of $548 collected for tickets to the school play. The adult tickets cost $6, and

the student tickets cost $4. If 12 more student tickets were sold than adult tickets, find the
numbers of adult and student tickets sold.

A=50

S=62

S Tickets= $4 each

A Tickets = $6 each
S Tickets = 12 more than A

6+4= 10 and then divided by 548 is 54 remainder 8. If you add the remainder its 62 and subtract twelve its fifty. Add them together! Not sure if it helps

S = A + 12

6A + 4S = 548

Substitute A+12 for S in the second equation and solve for A. Insert that value into the first equation to solve for S. Check by putting both values into the second equation.

To solve this problem, we can create a system of equations based on the given information. Let's suppose the number of adult tickets sold is 'a' and the number of student tickets sold is 's'.

From the given information, we have the following equations:

1) Total amount collected from adult tickets: 6a
2) Total amount collected from student tickets: 4s
3) Total amount collected from all tickets: 548

We also know that 12 more student tickets were sold than adult tickets:

4) s = a + 12

We can now rewrite equation 3) in terms of equations 1) and 2):

6a + 4s = 548

Now, substitute equation 4) into the rewritten equation 3):

6a + 4(a + 12) = 548
6a + 4a + 48 = 548
10a + 48 = 548
10a = 548 - 48
10a = 500
a = 500 / 10
a = 50

Now, substitute the value of 'a' back into equation 4) to find the value of 's':

s = a + 12
s = 50 + 12
s = 62

Therefore, 50 adult tickets and 62 student tickets were sold.