Net Ionic equation for
1. Iron(II) Iodide and Magnesium Acetate
2. Ammonium Phosphate and Cobalt(III) Chloride
3. Sodium Acetate and Potassium Chloride
These are the only ones I have left on my HW and I can't seem to figure them out would appreciate some help.
1 and 3 don't react so just the aq ions of those materials present. No ppts, no gases, etc.
2 forms CoPO4(s)
PO4^3- + Co^3+ ==> CoPO4
Sure, no problem! I can help you with that. Let's start with the net ionic equations for each of the given reactions:
1. Iron(II) Iodide and Magnesium Acetate
The chemical equation for this reaction is:
FeI2(aq) + Mg(CH3COO)2(aq) → Fe(CH3COO)2(aq) + MgI2(aq)
To write the net ionic equation, we need to identify the ions that are present in the solution and participate in the reaction. In this case, the spectator ions are I^- from FeI2 and CH3COO^- from Mg(CH3COO)2. The net ionic equation can be written as:
Fe^2+(aq) + 2(CH3COO)^-(aq) → 2(CH3COO)^-(aq) + Fe^2+(aq)
2. Ammonium Phosphate and Cobalt(III) Chloride
The chemical equation for this reaction is:
(NH4)3PO4(aq) + CoCl3(aq) → (NH4)3PO4(aq) + CoPO4(s)
For this reaction, the spectator ions are NH4+ from (NH4)3PO4 and Cl^- from CoCl3. The net ionic equation can be written as:
3PO4^3-(aq) + Co^3+(aq) → CoPO4(s)
3. Sodium Acetate and Potassium Chloride
The chemical equation for this reaction is:
CH3COONa(aq) + KCl(aq) → CH3COOK(aq) + NaCl(aq)
The spectator ions in this reaction are Na+ from CH3COONa and Cl^- from KCl. The net ionic equation is:
CH3COO^-(aq) + K+(aq) → CH3COOK(aq)
I hope this helps! Let me know if you have any further questions.
Sure! I can help you with that. To write the net ionic equations, we need to first write the balanced chemical equations for the given reactions.
1. Iron(II) Iodide and Magnesium Acetate:
The balanced chemical equation for this reaction is:
2 FeI2(aq) + 3 Mg(C2H3O2)2(aq) → 2 Fe(C2H3O2)3(aq) + 3 MgI2(aq)
The net ionic equation can be obtained by removing the spectator ions, which are ions that appear on both sides of the equation. In this case, the spectator ions are iodide (I-) and acetate (C2H3O2-) ions. The net ionic equation is:
2 Fe2+(aq) + 3 Mg2+(aq) → 2 Fe3+(aq) + 3 Mg2+(aq)
2. Ammonium Phosphate and Cobalt(III) Chloride:
The balanced chemical equation for this reaction is:
(NH4)3PO4(aq) + 3 CoCl3(aq) → 3 NH4Cl(aq) + Co3(PO4)2(s)
The net ionic equation can be obtained by removing the spectator ions. In this case, the spectator ions are ammonium (NH4+) and chloride (Cl-) ions. The net ionic equation is:
3 PO4^3-(aq) + 3 Co3+(aq) → Co3(PO4)2(s)
3. Sodium Acetate and Potassium Chloride:
The balanced chemical equation for this reaction is:
NaC2H3O2(aq) + KCl(aq) → NaCl(aq) + KC2H3O2(aq)
The net ionic equation can be obtained by removing the spectator ions. In this case, the spectator ions are sodium (Na+) and chloride (Cl-) ions. The net ionic equation is:
C2H3O2^-(aq) + K+(aq) → KC2H3O2(aq)
Remember to double-check the balancing of the chemical equations and ensure the charges on each side of the net ionic equations are balanced.