These are the answers i wanted corrected:
4x12/4x
d+7/d^2-49
t^2-25/t^2+t-20
2x^2+6x+4/4x^2-12x-16
6-y/y^2-2y-24
You will have to use brackets to show the intended order of operation.
How can we 'correct' your work if you supply neither solutions nor answers?
I will be happy to critique your work.
To correct the expressions, we need to follow the correct order of operations and use parentheses to clarify the intended grouping of terms. Here are the corrected expressions:
1. 4x(12/4x)
To simplify, we can cancel out the common factor of 4x:
= 12/1
= 12
2. (d+7)/(d^2-49)
We can factor the denominator as a difference of squares: (d+7)(d-7).
= (d+7)/(d+7)(d-7)
The common factor of (d+7) can be canceled out:
= 1/(d-7)
3. (t^2-25)/(t^2+t-20)
We can factor the numerator as a difference of squares: (t+5)(t-5).
We can factor the denominator by finding two numbers that multiply to -20 and add up to +1. Those numbers are +5 and -4.
= (t+5)(t-5)/[(t+5)(t-4)]
The common factor of (t+5) can be canceled out:
= (t-5)/(t-4)
4. (2x^2+6x+4)/(4x^2-12x-16)
We can factor both the numerator and denominator:
Numerator: (2x+2)(x+2)
Denominator: 4(x+2)(x-2)
= (2x+2)(x+2)/[4(x+2)(x-2)]
The common factor of (x+2) can be canceled out:
= (2x+2)/(4x-8)
Simplifying:
= (2(x+1))/4(x-2)
= (x+1)/(2x-4)
= (x+1)/(2(x-2))
5. (6-y)/(y^2-2y-24)
We can factor the denominator by finding two numbers that multiply to -24 and add up to -2. Those numbers are -6 and +4.
= (6-y)/[(y-6)(y+4)]
These are the corrected expressions. If you have any further questions or need clarification, please let me know!