Consider a 0.15m calcium chloride aqueous solution
a) determine the molarity of all solution. Assume that calcium chloride completely ionizes when dissolved in water. All solutes means all cations and anions.
b)
Is this0.15 m or 0.15 M
Is there a part b?
To determine the molarity of a solution, we need to know the moles of solute and the volume of the solution. Let's solve this step by step.
a) To find the molarity of a 0.15m calcium chloride aqueous solution, we need to know the moles of calcium chloride in a given volume of the solution.
Calcium chloride, CaCl2, dissolves completely in water, which means it ionizes into its constituent ions: Ca2+ and 2Cl-. Therefore, when we determine the moles of calcium chloride, we are essentially determining the moles of both calcium ions and chloride ions.
The molarity (M) of a solution is defined as the number of moles of solute per liter of solution. In this case, the solute is calcium chloride.
To calculate the moles of calcium chloride, we need to use its molar mass, which is the sum of the molar masses of calcium (Ca) and chlorine (Cl) atoms. The molar mass of calcium is 40.08 g/mol, and the molar mass of chlorine is 35.45 g/mol. Since calcium chloride has two chlorine ions, we multiply the molar mass of chlorine by 2.
Molar mass of CaCl2 = 40.08 g/mol + (35.45 g/mol x 2) = 110.98 g/mol
Now, we can calculate the moles of calcium chloride using the formula:
moles = mass / molar mass
Since we're given a 0.15m solution, we need to determine the mass of calcium chloride present in 1 liter (1000 mL) of the solution. The molarity (M) of a solution is given by the equation:
Molarity (M) = moles / volume (in liters)
First, convert the 0.15m to moles per liter by multiplying by the molar mass:
moles per liter = 0.15 mol/L * 110.98 g/mol = 16.647 g/L
Therefore, the molarity of the calcium chloride solution is 0.15 mol/L or 0.15 M.
b) It seems that the second part of your question is missing. If you have any further inquiries, please let me know and I'll be happy to assist you.