maths

if x =tan a +sin a and y =tan a -sin a prove that [x+y/x-y]^2x+y/2]^2=1

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  1. I let a = 20° and tested your equation
    the way you typed it, it is not true

    did you mean:
    [(x+y)/(x-y)]^(2x)+y/2]^2=1 ?
    or
    [( (x+y)/(x-y)]^2 )x)+y/2]^2=1 ?
    or
    ....

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