Before 1986, a gold bullion in the Federal Reserve Bank was rectangular and had a volume of approximately 727.7 cm3. The density of gold is 19.3 g/cm3. A pound is approximately 454 g. Find the weight of one gold bullion to the nearest tenth of a pound
727.7cm^3 * 19.3g/cm^3 = 14,045 g.
Wt. = 14,045g * 1Lb/454g = 30.9 Lbs.
To find the weight of one gold bullion, we need to use the given information.
First, we need to calculate the mass of the gold bullion. We can do this by multiplying its volume by the density of gold:
Mass = Volume x Density
Given:
Volume = 727.7 cm^3
Density = 19.3 g/cm^3
Substituting the values:
Mass = 727.7 cm^3 x 19.3 g/cm^3
Mass = 14,041.61 g
Next, we need to convert the mass from grams to pounds.
Since 1 pound is approximately 454 grams:
Weight in Pounds = Mass in Grams / Conversion Factor
Weight in Pounds = 14,041.61 g / 454 g/lb
Weight in Pounds ≈ 30.8 lb
Therefore, the weight of one gold bullion is approximately 30.8 pounds (to the nearest tenth of a pound).