Pre Cal

An airplane travels due west for 2.5 hours at 340 miles per hour. Then it changes course to S51°W. Find the airplanes distance from its point of departure and its bearing, after a total flight time of 4.5 hours.

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  1. Using the law of cosines, the distance z is

    z^2 = (2.5*340)^2 + (2*340)^2 - 2(2.5*340)(2*340)cos(141°)
    z = 1443

    bearing: 90-θ where
    tanθ = (2*340*cos51°)/(2.5*340+2*340*sin51°)
    θ = E 17.25° N
    or 72.75°

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