A sample on analysis shows 50% cao what will be the % of calcium carbonate in it
Let's take a 20 g sample which means 10 g CaO and 10 g impurity.
Convert 10 g CaO to ? g CaCO3. That's 10 x (molar mass CaCO3/ molar mass CaO)= about 18 g CaCO3 but you need a more accurate answer.
Total mass sample now is 18 + 10 = approx 28 and
% CaCO3 = (18/28)*100 = approx ?
To determine the percentage of calcium carbonate in a sample with 50% CaO (calcium oxide), you need to know the molecular weights and chemical formulas of both compounds.
The molecular weight of calcium oxide (CaO) is 56.08 g/mol, and the molecular weight of calcium carbonate (CaCO3) is 100.09 g/mol.
First, calculate the amount of calcium (Ca) present in the calcium oxide (CaO) using the given percentage:
% Ca in CaO = 50%
Molar mass of CaO = 56.08 g/mol
Mass of Ca in CaO = (50/100) * molar mass of CaO
Next, calculate the mass of calcium carbonate (CaCO3) that would contain the same amount of calcium:
Molar mass of CaCO3 = 100.09 g/mol
Molar mass of Ca = 40.08 g/mol
Mass of Ca in CaCO3 = Mass of Ca in CaO
Mass of CaCO3 = (Mass of Ca in CaO / Molar mass of Ca) * Molar mass of CaCO3
Finally, calculate the percentage of calcium carbonate in the sample:
% CaCO3 = (Mass of CaCO3 / Total mass of the sample) * 100
Plug in the values for the calculations above to get the percentage of calcium carbonate in the sample.