If 8.723 grams of sodium bicarbonate are dissolved in water to produce a 250.0mL solution, what is the morality of this solution?
I'm sorry but I don't have any equations or formulas to measure morality. If you want molarity, however, it is:
mols NaHCO3 = grams/molar maqss
Then M = molarity = mols/L solution
To determine the molarity (M) of a solution, you need to know the number of moles of solute (in this case, sodium bicarbonate) and the volume of the solution.
First, let's find the number of moles of sodium bicarbonate:
moles = mass / molar mass
The molar mass of sodium bicarbonate (NaHCO3) is:
Sodium (Na) = 22.99 g/mol
Hydrogen (H) = 1.01 g/mol
Carbon (C) = 12.01 g/mol
Oxygen (O) = 16.00 g/mol
Adding these values gives us the molar mass of sodium bicarbonate:
molar mass (NaHCO3) = 22.99 + 1.01 + (12.01 + 3 * 16.00) = 84.01 g/mol
Now, let's substitute the given values into the formula:
moles = 8.723 g / 84.01 g/mol
Using a calculator, we find:
moles ≈ 0.104 moles
Next, we calculate the molarity:
molarity (M) = moles / volume
Volume needs to be converted to liters since the unit of molarity is moles per liter:
volume = 250.0 mL = 250.0 mL * (1 L / 1000 mL) = 0.250 L
Finally, we substitute the values into the formula:
molarity (M) = 0.104 moles / 0.250 L
Using a calculator, we find:
molarity (M) ≈ 0.416 M
Therefore, the molarity of the solution is approximately 0.416 M.