The width of a rectangle is 6 centimeters less than the lenght. The perimeter is 64 centimeteres . would you please help me, answer these work. than you.

L = length
W = width
================
eqn 1:
2L + 2W = perimeter = 64 cm

eqn 2:
W+6cm = L
Solve the two equations simultaneously for W and L.
Post your work if you get stuck.

Well I don't know How to get it if I have to multiply or od i 2L + 2w what do I do I' m sorry but have so much trouble do in these work

You need to read your text or your notes on how to solve simultaneous equations. Basically, you solve for L in terms of W to eliminate one of the unknowns, then solve for that unknown.

well i only have the the question and that it these is what is in the book . Two angles of a triangle are 40 degrees and 62 degrees; what is the third angle's measure?

the width of a rectangle is 6 centimeters than the length . the perimeter is 64 centimeters . zI soryy but that's all i have in my book.

2L + 2W = 64cm

W + 6cm = L

substitue the value of L back into the first formula.

2(W + 6cm)+ 2W = 64cm
2W + 12cm + 2W = 64cm
4W + 12cm = 64cm
4W = 64cm - 12cm
4W = 52cm
W = 52cm/4
W= 13cm

therefore L = W + 6cm

substitue the value of W into the equation above to find the value of L.

L = 13cm + 6cm
L = 19cm

To solve the problem, follow these steps:

1. Let L represent the length of the rectangle.
2. Given that the width is 6 centimeters less than the length, we can express the width as W = L - 6.
3. The perimeter of a rectangle is found by adding the lengths of all four sides, which for this rectangle is 2L + 2W.
4. The problem states that the perimeter is 64 centimeters, so we can write the equation 2L + 2W = 64.
5. Now we have two equations:
- Equation 1: 2L + 2W = 64
- Equation 2: W = L - 6
6. To solve the system of equations, we can substitute the value of W from Equation 2 into Equation 1.
7. Substituting W = L - 6 into Equation 1, we get: 2L + 2(L - 6) = 64.
8. Simplifying this equation, we have 2L + 2L - 12 = 64.
9. Combining like terms, we get 4L - 12 = 64.
10. Adding 12 to both sides of the equation, we obtain 4L = 76.
11. Dividing both sides of the equation by 4, we find L = 19.
12. Now, substitute the value of L back into Equation 2 to find W: W = 19 - 6 = 13.
13. The length of the rectangle is 19 centimeters, and the width is 13 centimeters.

Therefore, the length of the rectangle is 19 centimeters and the width is 13 centimeters.