a 75kg parent and a 22kg child meet at the center of an ice rink. they place their hands together and push hard enough to slide apart.
a. is the force experienced by the child more than, less than, or the same force experienced by the parent? I said they experience the same force according to Newton's third law which forces in opposite directions have and equal magnitude of force.
b. is the acceleration of the child more than, less than, or the same acceleration as the parent? I said that the child has more acceleration because of the force exerted on him.
The rest of these questions I did not understand how to answer them.
c. if the acceleration of the child is 2.3 m/s2 in magnitude, what is the magnitude of the force of the parent's push on the child?
d. so what is the magnitude of the child's push on the parent?
e. what is the parents acceleration?
c. To find the magnitude of the force of the parent's push on the child, you can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a). Since you know the mass of the child (22 kg) and the magnitude of the acceleration (2.3 m/s^2), you can calculate the force using the formula F = m * a. Therefore, the magnitude of the force of the parent's push on the child would be F = 22 kg * 2.3 m/s^2.
d. The magnitude of the child's push on the parent would be equal in magnitude but opposite in direction to the force experienced by the child. This is because of Newton's third law of motion, which states that for every action, there is an equal and opposite reaction. So, the magnitude of the child's push on the parent would be the same as the magnitude of the force of the parent's push on the child (which was found in part c).
e. To find the parent's acceleration, you can again use Newton's second law of motion. Since you know the mass of the parent (75 kg) and the magnitude of the force exerted by the child's push (which was found in part d), you can calculate the acceleration using the formula a = F / m. Therefore, the parent's acceleration would be a = F / 75 kg, where F is the magnitude of the child's push on the parent (found in part d).