I've been stuck on this physics homework since I got home. I think the main issue I don't get is finding the components, and adding them to find the resultant force or velocity. Here's one problem.

Three forces act on a point concurrently. Force a is 80N at 220 degrees, force b is 70N at 90 degrees, and force c is 70N at 0 degrees. Find the resultant force and equilibrant force.

Please help in anyway, I really do not understand any of this.

x components:

80 cos 220 = -61.3
70 cos 90 = 0
70 cos 0 = 70
total x = 8.72
y components
80 sin 220 = -51.4
70 sin 90 = 70
70 sin 0 = 0
total y = 18.6
so magnitude resultant = sqrt (18.6^2 +8.72^2) = 20.2 Newtons
direction
cos angle = 8.72/20.2
angle = 64.4 degrees

The equilibrant is equal in magnitude and at 64.4+180 = 244.4 degrees

Equilibrant =0

quation of physics

Sure, I'd be happy to help you understand how to solve this problem.

To find the resultant force, we first need to find the x-component and y-component of each force. We can do this using trigonometry. The x-component is the force multiplied by the cosine of the angle, and the y-component is the force multiplied by the sine of the angle.

For force a:
x-component of a = 80N * cos(220 degrees)
y-component of a = 80N * sin(220 degrees)

For force b:
x-component of b = 70N * cos(90 degrees)
y-component of b = 70N * sin(90 degrees)

For force c:
x-component of c = 70N * cos(0 degrees)
y-component of c = 70N * sin(0 degrees)

Once we have the x and y components of each force, we can add them together to find the resultant force in terms of x and y components. The x-component of the resultant force is the sum of the x-components of all the forces, and the y-component of the resultant force is the sum of the y-components of all the forces.

x-component of resultant force = x-component of a + x-component of b + x-component of c
y-component of resultant force = y-component of a + y-component of b + y-component of c

Finally, we can find the magnitude and direction of the resultant force using the Pythagorean theorem and inverse trigonometric functions. The magnitude is the square root of the sum of the squares of the x and y components, and the direction is the arctangent of the y component divided by the x component.

Magnitude of resultant force = sqrt( (x-component of resultant force)^2 + (y-component of resultant force)^2 )
Direction of resultant force = tan^(-1)( y-component of resultant force / x-component of resultant force )

To find the equilibrant force, we need to find a force that is equal in magnitude but opposite in direction to the resultant force. This means that the x component of the equilibrant force is the negative of the x component of the resultant force, and the y component of the equilibrant force is the negative of the y component of the resultant force.

I hope this helps you understand how to find the resultant force and equilibrant force in this problem. Let me know if you have any more questions!