A wire of length 20 cm and carrying a current of 2.5 A makes an angle of 30o
with a magnetic
field of strength 0.8 T. Calculate the magnitude of the force on the wire.
My Working:
F=BILSindeta
F=0.8*2.5*0.2*sin30=0.2N
is this correct?
Yes, your working is correct. Let's break down the steps to calculate the magnitude of the force on the wire using the formula:
F = BILsinθ
We are given:
Length of the wire (L) = 20 cm = 0.2 m
Current (I) = 2.5 A
Magnetic field strength (B) = 0.8 T
Angle between the wire and the magnetic field (θ) = 30 degrees
Substituting the given values into the formula:
F = (0.8 T) * (2.5 A) * (0.2 m) * sin(30 degrees)
F = 0.2 N
So, the magnitude of the force on the wire is 0.2 N. Therefore, your solution is correct.