My seven year old was set this question and I was asked to solve. Help please.
Here is the question:
My number has 5 tens. The ones digit is less than the tens. What could the number be?
My solution was 5 x 10 = 50. Then subtract 1 from the tens = 49 is this correct?
5 tens = 50
ones digit is less than the tens
54, 53, 52, 51, 50
To solve this question, we need to find a number that has 5 tens and a ones digit that is less than the tens digit.
First, let's write down the place value of each digit in the number:
Tens digit: __
Ones digit: __
We know that the number has 5 tens. Therefore, the tens digit is 5:
Tens digit: 5
Ones digit: __
Next, we are given that the ones digit is less than the tens digit. So, the ones digit can be any number less than 5 (0, 1, 2, 3, or 4). Let's try each possibility and find the numbers:
1) If the ones digit is 0:
The number would be 50. However, 0 is not less than 5 (tens digit), so this option doesn't work.
2) If the ones digit is 1:
The number would be 51. 1 is less than 5 (tens digit), so this option works.
3) If the ones digit is 2:
The number would be 52. 2 is less than 5 (tens digit), so this option works.
4) If the ones digit is 3:
The number would be 53. 3 is less than 5 (tens digit), so this option works.
5) If the ones digit is 4:
The number would be 54. 4 is less than 5 (tens digit), so this option works.
So, the possible numbers that meet the given conditions are 51, 52, 53, and 54.
In conclusion, your solution of 49 is not correct because it does not have 5 tens. The correct answer is that the number could be 51, 52, 53, or 54.