Problem
Lejon can finish a job in 6 hours while Romel can do the same job in 3 hours. Working together, how many hours can they finish the job?
T = t1*t2/(t1+t2).
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To solve this problem, we can use the concept of work rates.
First, let's find the work rate of each person. Lejon can finish the job in 6 hours, so his work rate is 1/6 of the job per hour (1 job divided by 6 hours). Romel can finish the job in 3 hours, so his work rate is 1/3 of the job per hour.
When they work together, we can add their work rates to find the combined work rate. So the combined work rate is 1/6 + 1/3 = 1/6 + 2/6 = 3/6.
To find how long it would take them to finish the job together, we can take the reciprocal of the combined work rate. The reciprocal of 3/6 is 6/3, which simplifies to 2.
Therefore, Lejon and Romel can finish the job together in 2 hours.