What mass of iodine would react with 48 grams of magnesium to make magnesium iodide?
To determine the mass of iodine required to react with 48 grams of magnesium to produce magnesium iodide, we can use the balanced chemical equation for the reaction between magnesium and iodine:
2 Mg + I2 → 2 MgI2
From the equation, we can see that it takes two moles of magnesium (2Mg) to react with one mole of iodine (I2) to form two moles of magnesium iodide (2MgI2).
To find the molar mass of iodine, we need to look it up on the periodic table. Iodine has an atomic mass of approximately 126.9 grams/mol.
Now, let's calculate the number of moles of magnesium in 48 grams:
Molar mass of magnesium (Mg) = 24.3 grams/mol
Number of moles = Mass / Molar mass = 48 g / 24.3 g/mol = 1.98 moles (approximately)
Since magnesium and iodine react in a 1:1 ratio, the number of moles of iodine required will be the same as the number of moles of magnesium. Therefore, we need 1.98 moles of iodine.
Finally, we can calculate the mass of iodine needed using the molar mass of iodine:
Mass of iodine = Number of moles × Molar mass
Mass of iodine = 1.98 moles × 126.9 g/mol = 251.5 grams (approximately)
So, approximately 251.5 grams of iodine would react with 48 grams of magnesium to form magnesium iodide.
To determine the mass of iodine that would react with 48 grams of magnesium to form magnesium iodide, we need to use the balanced chemical equation for the reaction between magnesium and iodine.
The balanced chemical equation for the reaction is:
Mg + I2 → MgI2
From the equation, we can see that one mole of magnesium reacts with one mole of iodine to form one mole of magnesium iodide.
Step 1: Calculate the molar mass of magnesium (Mg):
The molar mass of magnesium (Mg) is 24.31 grams per mole.
Step 2: Convert the given mass of magnesium to moles:
To convert grams to moles, divide the mass by the molar mass.
Moles of magnesium = (Given mass of magnesium) / (Molar mass of magnesium)
Moles of magnesium = 48 grams / 24.31 grams per mole
Moles of magnesium = 1.975 moles
Step 3: Determine the molar ratio between magnesium and iodine:
From the balanced chemical equation, the molar ratio between magnesium and iodine is 1:1. This means that one mole of magnesium reacts with one mole of iodine.
Step 4: Calculate the moles of iodine:
Since the molar ratio between magnesium and iodine is 1:1, the moles of iodine will be the same as the moles of magnesium.
Moles of iodine = Moles of magnesium = 1.975 moles
Step 5: Convert the moles of iodine to grams:
To convert moles to grams, multiply the moles by the molar mass of iodine.
Moles of iodine = 1.975 moles
Molar mass of iodine (I2) = 253.8089 grams per mole
Mass of iodine = Moles of iodine * Molar mass of iodine
Mass of iodine = 1.975 moles * 253.8089 grams per mole
Mass of iodine = 500.941 grams
Therefore, to react with 48 grams of magnesium to form magnesium iodide, we would need 500.941 grams of iodine.
508 grams
Mg + I2 ==> MgI2
mols Mg = grams/molar mass
Using the coefficients in the balanced equation, convert mols Mg to mols I2. that's a 1:1 reaction.
Now convert mols Mg to grams. g = mols MgI2 x molar mass MgI2.