A 300lb car is moving at constant velocity onn a level concrete road. How much force is needed to keep it moving if the u=0.04

M = 300Lbs * 0.454kg/Lb = 136.2 kg.

Fk = u*Fn = u*Mg = 0.04 * (136.2*9.8) = 53.4 N. = Force of kinetic friction.

Fap-Fk = M*a.
Fap-53.4 = M*0 = 0, Fap = 53.4 N. = Force applied.

Well, to keep a 300lb car moving on a level road with a coefficient of friction of 0.04, you'll need to call in the "Force Whisperer"! Don't worry, it's not as intimidating as it sounds.

Using Newton's second law (F = m*a), we can find the force required. In this case, the car is moving at a constant velocity, which means the net force acting on it is zero. Pretty cool, huh? So, the force needed to counteract the friction can be calculated using the equation F_friction = u * F_normal, where u is the coefficient of friction and F_normal is the normal force.

In this case, the normal force is equal to the weight (mass * gravitational acceleration), which is approximately 300lbs or 136kg.

Now, we can plug in the values:
F_friction = 0.04 * 136kg ≈ 5.44kg

Therefore, approximately 5.44kg of force is needed to keep the 300lb car moving at a constant velocity on the level road. Just make sure the "Force Whisperer" doesn't get too carried away with this one!

To determine the force needed to keep the car moving at a constant velocity, we can use the equation:

Force of friction (Ff) = coefficient of friction (μ) × normal force (Fn)

The normal force (Fn) is equal to the weight of the car, which can be calculated by multiplying the mass of the car (in this case, given as 300 lbs) by the acceleration due to gravity (9.8 m/s^2):

Weight (W) = mass (m) × acceleration due to gravity (g)

First, let's convert the weight of the car from pounds to kilograms as the SI unit for weight is in Newtons:

1 lb ≈ 0.4536 kg

So, the weight of the car is:
W = 300 lbs × 0.4536 kg/lb

To calculate the normal force, we can now substitute the values into the equation:

Fn = W = 300 lbs × 0.4536 kg/lb × 9.8 m/s^2

Now, we can calculate the force of friction using the equation:

Ff = μ × Fn

Substituting the values:

Ff = 0.04 × (300 lbs × 0.4536 kg/lb × 9.8 m/s^2)

By performing the calculation, we can determine the force of friction needed to keep the car moving at a constant velocity.

To determine the force needed to keep the 300lb car moving at a constant velocity on a level concrete road with a coefficient of friction (μ) of 0.04, we can use the equation:

Frictional Force (Ff) = μ * Normal Force (Fn)

The normal force (Fn) is the force exerted by the road on the car in the upward direction. Since the car is on a level road, the normal force is equal to its weight (W).

Weight (W) = mass * acceleration due to gravity

First, let's convert the weight of the car from pounds to kilograms, using the fact that 1lb = 0.4536kg:

Mass = Weight (in kg) / acceleration due to gravity
Mass = 300lb * 0.4536kg/lb = 136.08 kg

Now, we can calculate the normal force exerted by the road:

Fn = Weight = Mass * acceleration due to gravity ≈ 136.08 kg * 9.8 m/s² = 1334.784 N

Lastly, we can calculate the frictional force:

Ff = μ * Fn = 0.04 * 1334.784 N ≈ 53.392 N

Therefore, approximately 53.392 Newtons of force is needed to keep the 300lb car moving at a constant velocity on a level concrete road with a coefficient of friction of 0.04.