1. A 70-kg box is slid along the floor by a 400-N. The coefficient of friction between the box and the floor is 0.50 when the box is sliding. Find the acceleration of the box.
what is the net horizontal force on the box?
F = ma
it doesn't tell me. the teacher only gave me the this question and that is the only information
To find the acceleration of the box, we will use Newton's second law of motion, which states that the acceleration of an object is equal to the net force acting on it divided by its mass.
First, let's calculate the force of friction. The force of friction can be determined using the equation:
Force of friction = coefficient of friction * Normal force
The normal force is the force exerted by the surface perpendicular to the object. In this case, since the box is sliding along the floor, the normal force is equal to the weight of the box, which can be calculated using the equation:
Weight = mass * gravitational acceleration
where the mass is given as 70 kg and the gravitational acceleration is approximately 9.8 m/s^2.
Weight = 70 kg * 9.8 m/s^2 = 686 N
Now we can find the force of friction:
Force of friction = 0.50 * 686 N = 343 N
The net force acting on the box is the difference between the applied force (400 N) and the force of friction (343 N):
Net force = 400 N - 343 N = 57 N
Now we can find the acceleration using Newton's second law:
acceleration = Net force / mass
acceleration = 57 N / 70 kg = 0.81 m/s^2
Therefore, the acceleration of the box is 0.81 m/s^2.