(x-3)^2+(y-2.5)^2=7.25
Make a new equation that shifts up 1 unit and to the right 2 units.
I got (x-5)^2+(y-1.5)^2=7.25, but I got it wrong on my test. Could you please tell me where I might have gone wrong?
Thank you!
You did not subtract 1 from 2.5 in the y to get (y-3.5)^2
But if it shifts up 1 unit shouldn't I add it to the y?
To shift the equation (x-3)^2 + (y-2.5)^2 = 7.25 up 1 unit and to the right 2 units, you need to adjust the equation accordingly.
Let's start by shifting the equation up 1 unit. To do this, you need to replace the constant term (-2.5)^2 in the original equation with (-2.5 + 1)^2, because the y-coordinate is shifting up by 1 unit. Similarly, the constant term (-3)^2 needs to be replaced with (-3 + 1)^2 to shift the x-coordinate 2 units to the right.
So, the modified equation would be:
(x - (3 - 2))^2 + (y - (2.5 - 1))^2 = 7.25
Simplifying this equation, we get:
(x - 1)^2 + (y - 1.5)^2 = 7.25
Therefore, the correct equation that shifts the original equation up 1 unit and to the right 2 units is (x - 1)^2 + (y - 1.5)^2 = 7.25.
It seems like you made a mistake when adjusting the constant terms. Instead of subtracting the shift values from the original coordinates, you need to subtract them from the constant terms in the equation.