The second hand on a watch has a length of 4.50 mm and makes one revolution in 60.00 s.
What is the speed of the end of the second hand as it moves in uniform circular motion?
I just need some help getting started
What is the circumference of the circle the end of the hand scribes? You are given the radius.
speed=distance/time
no the radius is not given. The question i posted is all i have to work with.
The length of the hand is the radius.
Tangina ano sagot??
To find the speed of the end of the second hand as it moves in uniform circular motion, we need to understand the definition of speed in circular motion.
Speed in circular motion is given by the formula:
v = ω * r
where v is the speed, ω is the angular velocity, and r is the radius of the circular path.
In this case, the second hand makes one revolution (360 degrees) in 60.00 s. We can use this information to calculate the angular velocity.
The angular velocity is given by:
ω = Δθ / Δt
where Δθ is the change in angle and Δt is the change in time.
Since the second hand makes one revolution (360 degrees), Δθ = 360 degrees or 2π radians.
Given that Δt = 60.00 s, we can substitute these values into the formula to find ω.
ω = (2π rad) / (60.00 s)
Next, we need to find the radius of the circular path. In this case, the length of the second hand represents the circumference of the circle. The formula for the circumference of a circle is:
C = 2πr
where C is the circumference and r is the radius.
Given that the length of the second hand is 4.50 mm, we can equate this to the circumference and solve for r.
4.50 mm = 2πr
After solving for r, we now have all the values we need to calculate the speed.
Substitute the values of ω (angular velocity) and r (radius) into the formula for speed:
v = ω * r
Calculate the product of ω and r to find the speed of the end of the second hand.