A poster is 3 inches long. its 4 times as wide as it is long.
a. draw a diagram of the poster and label its diagram
b. find the perimeter and area of the poster
the perimeter is 30 because the width is 3 and the length is 4 times the width,(4 times 3 = 12) and then add all the sides so you would have 3+12+3+12=30
a. To draw the diagram of the poster, start by drawing a rectangle shape and labeling it with the given measurements. Since the poster is 3 inches long and 4 times wider than its length, the width can be found by multiplying the length by 4. Therefore, the width of the poster is 3 inches multiplied by 4, which equals 12 inches. Label the length as "3 inches" and the width as "12 inches" on the diagram.
b. To find the perimeter of the poster, you can add up all the sides of the rectangle. The perimeter of a rectangle is calculated by adding the lengths of all four sides. In this case, the rectangle has two sides with a length of 3 inches and two sides with a length of 12 inches.
Perimeter = 2 * Length + 2 * Width
Perimeter = 2 * 3 inches + 2 * 12 inches
Perimeter = 6 inches + 24 inches
Perimeter = 30 inches
Therefore, the perimeter of the poster is 30 inches.
To find the area of the poster, you can multiply the length and width of the rectangle.
Area = Length * Width
Area = 3 inches * 12 inches
Area = 36 square inches
Therefore, the area of the poster is 36 square inches.