The perimeter of a rectangular field is 380 yd. The length is 70 yd longer than the width. Find the dimensions.
Please help
2(w + w+70) = 380
To find the dimensions of the rectangular field, we need to set up a system of equations based on the given information. Let's assign a variable to the width of the field.
Let's say the width of the rectangular field is x yards. According to the problem, the length is 70 yards longer than the width. So, the length can be represented as x + 70 yards.
The perimeter of a rectangle is calculated by adding all its sides. In this case, the perimeter is given as 380 yards. So we can set up an equation:
Perimeter = 2(Length + Width)
Substituting the given values, we have:
380 = 2(x + 70 + x)
Now we can solve this equation to find the value of x.
380 = 2(2x + 70)
380 = 4x + 140
240 = 4x
x = 60
Now that we have the width as 60 yards, we can find the length:
Length = Width + 70 = 60 + 70 = 130 yards
Therefore, the dimensions of the rectangular field are 60 yards (width) and 130 yards (length).