A rocket initially at rest accelerates at a rate of 80 m/s^2 for 0.74 min.
What is its speed at the end of this time? Answer in units of m/s.
Plz help and explain
v = at
plug in your numbers. watch the units.
but arent you supposed to look for the speed?
yes -- velocity = speed. Look at the units:
(m/s^2)*(s) = (m/s)
acceleration is how much the speed changes each second: (m/s)/s = m/s^2
so, in your example, the speed grows by 80m/s every second.
quantity = rate * time, such as
5 pages/day * 2 days = 10 pages
etc.
To find the speed of the rocket at the end of the given time, we can use the equation of motion:
v = u + at
Where:
v = final velocity
u = initial velocity (which is 0 m/s since the rocket is initially at rest)
a = acceleration
t = time
Given values:
u = 0 m/s (initial velocity)
a = 80 m/s^2 (acceleration)
t = 0.74 min = 0.74 × 60 = 44.4 seconds (converted to seconds)
Now, substitute the given values into the equation to find the final velocity:
v = 0 + (80 × 44.4)
Multiplying the values:
v = 3552 m/s
Therefore, the speed of the rocket at the end of 0.74 min is 3552 m/s.