if 5 kg mass is suspended from an ideal spring can oscillate down. If the amplitude of oscillator is doubled . the period will be?
a. Increases by factor 5
b. decreases by factor 5
c. double
d. remain same
the period is related to the mass and the spring constant
the amplitude is inconsequential
To find the period of an ideal spring oscillator, we need to calculate the time it takes for one complete oscillation cycle. The period is defined as the time taken to complete one full back-and-forth motion.
The period of an ideal spring oscillator is given by the formula:
T = 2π√(m/k)
Where:
T = Period
m = Mass
k = Spring constant
In this case, the mass is 5 kg. To determine the effect of doubling the amplitude on the period, we need to understand that the amplitude does not impact the period of an ideal spring oscillator. Therefore, doubling the amplitude will not affect the period.
Hence, the answer is:
d. remain same