Write the balanced chemical equation for the oxidation of catechol to
quinone.
To write the balanced chemical equation for the oxidation of catechol to quinone, we need to know the oxidation reactants and products.
The oxidation of catechol (C6H6O2) to quinone (C6H4O2) involves the loss of electrons. The oxidation reaction can occur in the presence of an oxidizing agent, such as oxygen or a strong oxidizing agent like potassium permanganate (KMnO4) or hydrogen peroxide (H2O2).
Let's assume the reaction is carried out using oxygen as the oxidizing agent. The balanced chemical equation for the oxidation of catechol to quinone using oxygen is as follows:
2 Catechol (C6H6O2) + O2 → 2 Quinone (C6H4O2) + 2 H2O
In this balanced equation, we have two molecules of catechol reacting with one molecule of oxygen gas. This results in the formation of two molecules of quinone and two molecules of water.
Remember, the process of balancing chemical equations involves ensuring that the number of atoms on both sides of the equation is the same.