Joe is playing a game with a regular die. if the number that turns up is even he will gain 5 times the number that comes up. if it is odd, he will lose 10
times the number that comes up. he tosses a 3. express the results as an integer
It will be -12 tonight the weatherman predicts it will be 25 warmer by noon tomorrow what will the temperature be by noon toworrow
How can I explain my answer
68 times
To determine Joe's result when he tosses a 3 with the conditions given, we follow the rules mentioned:
Since 3 is an odd number, Joe will lose 10 times the number that comes up. In this case, he will lose 10 x 3 = 30.
So, the result can be expressed as an integer: -30. This represents that Joe lost 30 in the game.
find the expected value of each case
1 comes up ---> 1/6 (-10) = -10/6
3 comes up ---> 1/6 (-30) = -30/6
5 comes up ---> 1/6 (-50) = -50/6
2 comes up ---> 1/6 (10) = 10/6
4 comes up ---> 1/6 (20) = 20/6
6 comes up ---> 1/6 (30) = 30/6
sum = 1/6 (-10 -30 -50 +10 +20 +30) = -30/6 = -5
I don't know what you are actually asking.
You say "he tosses a 3", so look at my case for 3.
Overall this is not a game I would play, in the long run you lose.