A car moves with constant velocity along a straight road. Its position is x1 = 0 m at t1 = 0 s and is x2 = 48m at t2 = 5.0s . Answer the following by considering ratios, without computing the car's velocity. What is the car's position at t = 2.5s ? What will be its position at t = 15s ?
x/2.5 = 48/5.0
and do the same for the other question.
okay so what's the answer
1.) 24m
2.) 144m
Is that correct?
To determine the car's position at t = 2.5s using ratios, we can use the concept of proportionality.
First, we calculate the ratio of the change in position to the change in time for the given time interval:
Ratio = (x2 - x1) / (t2 - t1)
Plugging in the given values, we have:
Ratio = (48m - 0m) / (5.0s - 0s)
Ratio = 48m / 5.0s
Ratio = 9.6 m/s
This ratio represents the constant velocity of the car. Now, to find the car's position at t = 2.5s, we can use this ratio:
Position at t = 2.5s = x1 + (t - t1) * Ratio
= 0m + (2.5s - 0s) * 9.6 m/s
= 0m + 2.5s * 9.6 m/s
= 24m
Therefore, the car's position at t = 2.5s is 24m.
To find the car's position at t = 15s, we can again use the ratio we calculated earlier:
Position at t = 15s = x1 + (t - t1) * Ratio
= 0m + (15s - 0s) * 9.6 m/s
= 0m + 15s * 9.6 m/s
= 144m
Therefore, the car's position at t = 15s is 144m.