Maths

Given that log200=0.3010 and log1000=0.4771 calculate without using table log0.72.

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  1. first, I think you mean to say that

    log 2 = 0.3010
    log 3 = 0.4771

    Now: 72 = 2^3 * 3^2
    so
    log 0.72 = 3log2 + 2log3 - 2

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  2. You are starting off with a wrong premise
    log 200 = 2.301, not as given
    log 1000 = 3, not as given

    If not stated, log x is assumed to have base 10
    If you are working with some mysterious unknown base, then
    loga 200 = .301
    a^.301 = 200
    .301 loga = log200
    a = 44,118,214.29

    check: 44118214.29^.301 = 200

    unfortunately your log 1000 = .4771 does not even that base.

    Check your question.

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