PLEASE HELP! I GUESS IT'S,C,Find the maximum and minimum values of the function 3x'square-2x'cube.[A=3,0] [B=2,0][C=1,0]
I read that your function is
f(x) = 3x^2 - 2x^3
and I will assume that [A=3,0] [B=2,0][C=1,0] are your answers stated in an unusual way.
lets' see ....
f ' (x) = 6x - 6x^2
for a max/min this equals zero
6x + 6x^2 = 0
6x( 1- x) = 0
x = 0 or x = 1
f(0) = 3(0) - 2(0) = 0
f(1) = 3(1) - 2(1) = 1
the max is (1,1), the min is (0,0)
check:
http://www.wolframalpha.com/input/?i=f(x)+%3D+3x%5E2+-+2x%5E3+from+-1+to+2
I have no idea what that other stuff is.