Find the roots for the given equstion

p^4+m^4=0

p^4+m^4

= (p^2+m^2 i)(p^2 - m^2 i)
= (p-m√i*i)(p+m√i*i)(p+m√i)(p-m√i)
= (p-m√i^3)(p+m√i^3)(p+m√i)(p-m√i)
= (p-m√-i)(p+m√-i)(p+m√i)(p-m√i)

I assume you can figure out what √i and √-i are. (de Moivre's law)