A bag of 7 blue marbles, 8 green marbles, 9 yellow marbles. If one marble is drawn from the bag but not replaced, what is the probability of drawing a blue marble then a yellow marble?
My answer is: 7/24 * 9/23 = 63/552 = 21/184
It is impossible to answer your question due to the fact we do not know what color the marble you drew first was. This decreases the odds randomly and cannot be mathematically calculated.
Your answer is correct! To calculate the probability of drawing a blue marble followed by a yellow marble, you need to multiply the individual probabilities of each event.
Let's break it down step by step:
First, you have 7 blue marbles out of a total of 7 + 8 + 9 = 24 marbles. So, the probability of drawing a blue marble on the first draw is 7/24.
After you draw a blue marble, you have taken it out of the bag, so there are now 23 marbles left. Out of these, you have 9 yellow marbles. Therefore, the probability of drawing a yellow marble on the second draw, given that you've already drawn a blue marble, is 9/23.
To find the probability of both events happening together, you multiply the individual probabilities: (7/24) * (9/23) = 63/552 = 21/184.
So, the probability of drawing a blue marble then a yellow marble from the bag, without replacement, is indeed 21/184.