An oceanic depth-sounding vessel surveys the

ocean bottom with ultrasonic waves that
travel 1530 m/s in seawater.
How deep is the water directly below the
vessel if the time delay of the echo to the
ocean floor and back is 7 s?
Answer in units of m.
plz help and explain

speed = distance/time

so, what is the round-trip distance?

To find the depth of the water directly below the vessel, we need to use the formula:

depth = (speed of sound in water * time delay) / 2

In this case, the speed of sound in seawater is given as 1530 m/s and the time delay of the echo is 7 s.

Plugging these values into the formula, we get:

depth = (1530 m/s * 7 s) / 2

depth = 10710 m / 2

depth = 5355 m

Therefore, the depth of the water directly below the vessel is 5355 meters.