# Physics

A 51kg person on a merry-go-round is traveling in a circle with a radius of 2 m at a speed of 6 m/s

A) What acceleration does the person experience?
B) What is the net horizontal force?
C) How does it compare with the person's weight?

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3. 👁 125
1. Ac = v^2/r = 36/2 = 18 m/s^2
m
F = M Ac = 51 *18 Newtons

weight = 51 * 9.81 Newtons

almost 2 g

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posted by Damon
2. acceleration= v^2/r
force=mass*acceleration
weight=51*9.8 N

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