a stone mass of 2.5kg is falling a certai height. Find the force of attraction between the earth and the stone. Also find its acceleration
if near earth surface
F = m g = 2.5 * 9.81 N
and acceleration is g = 9.81 m/s^2
if at great distance r from earth center you need to do
F = 2.5 G Mearth/r^2
so a = G Mearth/r^2
To find the force of attraction between the Earth and the stone, you can use the equation for gravitational force:
F = m * g
where F is the force, m is the mass of the object, and g is the acceleration due to gravity. In this case, the mass of the stone is given as 2.5 kg.
To find the value of g, you can use the standard value for acceleration due to gravity, which is approximately 9.8 m/s^2 on the surface of the Earth.
Plugging in the values, we get:
F = 2.5 kg * 9.8 m/s^2
F = 24.5 N
So, the force of attraction between the Earth and the stone is 24.5 Newtons.
Now, let's find the acceleration of the stone as it falls. The acceleration of a falling object near the surface of the Earth is equal to the acceleration due to gravity, which is approximately 9.8 m/s^2.
Therefore, the acceleration of the stone is 9.8 m/s^2.
In summary:
- The force of attraction between the Earth and the stone is 24.5 Newtons.
- The acceleration of the stone is 9.8 m/s^2.