# math condense logs

write the expression as the logarithm of a single quantity

3[ln x-2 ln(x^2+1)]+2 ln 5

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1. 3logx-6log(x^2+1)+log25
logx^3-log(x^2+1)+log25
logx^3+log25-log(x^2+1)^6
log(x^3*25/(x^2+1)^6))

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2. wait, may I ask you what happened to ln?

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3. it is the same thing bro log and ln

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4. ln is log base e

3[ln x-2 ln(x^2+1)]+2 ln 5

ln a - ln b = ln (a/b)
n ln x = ln x^n
so
3 ln [ x/(x^2+1)^2] + ln 25

ln 25[ x/(x^2+1)^2]^3
so agree with Sam

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