math condense logs

write the expression as the logarithm of a single quantity

3[ln x-2 ln(x^2+1)]+2 ln 5

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  1. 3logx-6log(x^2+1)+log25
    logx^3-log(x^2+1)+log25
    logx^3+log25-log(x^2+1)^6
    log(x^3*25/(x^2+1)^6))

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  2. wait, may I ask you what happened to ln?

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  3. it is the same thing bro log and ln

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  4. ln is log base e

    3[ln x-2 ln(x^2+1)]+2 ln 5

    ln a - ln b = ln (a/b)
    n ln x = ln x^n
    so
    3 ln [ x/(x^2+1)^2] + ln 25

    ln 25[ x/(x^2+1)^2]^3
    so agree with Sam

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