A BAG OF M&M'S HAS 3 RED, 7 GREEN, 6 BLUE AND 5 YELLOW M&M'S . WHAT IS THE PROBABILITY OF RANDOMLY PICKING.
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Randomly picking what Amanda, two reds and a green in three picks?
To determine the probability of randomly picking a specific color M&M from the bag, we need to know the total number of M&M's in the bag, as well as the number of M&M's of the specific color we are interested in.
In this case, we are interested in the probability of randomly picking an M&M of a specific color (red, green, blue, or yellow) from the bag. Let's calculate the probability for each color:
1. Red M&M's: The bag has a total of 3 red M&M's. So the probability of randomly picking a red M&M is 3/21 (since the total number of M&M's is 3 + 7 + 6 + 5 = 21).
2. Green M&M's: The bag has a total of 7 green M&M's. So the probability of randomly picking a green M&M is 7/21.
3. Blue M&M's: The bag has a total of 6 blue M&M's. So the probability of randomly picking a blue M&M is 6/21.
4. Yellow M&M's: The bag has a total of 5 yellow M&M's. So the probability of randomly picking a yellow M&M is 5/21.
Note that the total probability of picking any color M&M should add up to 1 because it represents the entire sample space (all possible outcomes).
Therefore, the probability of randomly picking a red M&M is 3/21, for a green M&M it is 7/21, for a blue M&M it is 6/21, and for a yellow M&M it is 5/21.