A 3.50 g sample of KCl is dissolved in 10.0 mL of water. The resulting solution is then added to 60.0 mL of a 0.500 M CaCl2(aq) solution. Assuming that the volumes are additive, calculate the concentrations of each ion present in the final solution.

*confused*

Change grams to mols for KCl.

Change 60.0 mL of 0.500 M solution CaCl2 to mols.
Write the ionization equation to show how the molecules break apart.
Note the mol ratios.
Calculate molarity which = #mols/L soln for each ion.
I don't think I've omitted a step but post your work if you get stuck.

To calculate the concentrations of each ion present in the final solution, we need to determine the moles of each ion.

First, let's start by finding the moles of KCl. We have a 3.50 g sample, and the molar mass of KCl is 74.55 g/mol.

moles of KCl = mass / molar mass
moles of KCl = 3.50 g / 74.55 g/mol
moles of KCl ≈ 0.0469 mol

Next, let's find the moles of CaCl2. We have a 0.500 M solution and a volume of 60.0 mL. Volume can be converted to liters by dividing by 1000.

moles of CaCl2 = concentration × volume
moles of CaCl2 = 0.500 mol/L × 60.0 mL / 1000 mL/L
moles of CaCl2 = 0.030 mol

Now, let's calculate the total moles of Cl ions present in the final solution. Each KCl molecule produces one Cl ion, and each CaCl2 molecule produces two Cl ions.

total moles of Cl ions = moles of KCl + (2 × moles of CaCl2)
total moles of Cl ions = 0.0469 mol + (2 × 0.030 mol)
total moles of Cl ions = 0.107 mol

To find the concentration of Cl ions in the final solution, divide the total moles of Cl ions by the total volume of the solution.

total volume of solution = volume of water + volume of CaCl2 solution
total volume of solution = 10.0 mL + 60.0 mL
total volume of solution = 70.0 mL = 0.070 L

concentration of Cl ions = total moles of Cl ions / total volume of solution
concentration of Cl ions = 0.107 mol / 0.070 L
concentration of Cl ions ≈ 1.53 M

Since KCl dissociates into one K+ ion and one Cl- ion, the concentration of K+ ions in the final solution will also be approximately 1.53 M.

Therefore, the concentrations of each ion present in the final solution are approximately 1.53 M for both K+ and Cl- ions.

To calculate the concentrations of each ion present in the final solution, we need to follow these steps:

Step 1: Calculate the number of moles of KCl dissolved in water.
The molar mass of KCl is the sum of the atomic masses of potassium (K) and chlorine (Cl), which is 39.10 g/mol + 35.45 g/mol = 74.55 g/mol.

To find the number of moles, divide the mass of KCl by its molar mass:
Number of moles of KCl = mass of KCl / molar mass of KCl.
Number of moles of KCl = 3.50 g / 74.55 g/mol.

Step 2: Calculate the concentration of KCl in the final solution.
The volume of the KCl solution is 10.0 mL, which is equivalent to 0.0100 L.
The concentration of KCl is given by:
Concentration of KCl = moles of KCl / volume of KCl solution.
Concentration of KCl = number of moles of KCl / 0.0100 L.

Step 3: Calculate the concentration of Ca2+ ions in the final solution.
The volume of the CaCl2 solution is 60.0 mL, which is equivalent to 0.0600 L.
The concentration of Ca2+ ions is given by the molarity, which is 0.500 M.

Step 4: Calculate the number of moles of Ca2+ ions in the final solution.
The number of moles of Ca2+ ions can be calculated by multiplying the concentration of Ca2+ ions by the volume of the CaCl2 solution:
Number of moles of Ca2+ ions = concentration of Ca2+ ions × volume of CaCl2 solution.

Step 5: Calculate the total volume of the final solution.
The total volume of the final solution is the sum of the volumes of the KCl solution and the CaCl2 solution, which is 0.0100 L + 0.0600 L = 0.0700 L.

Step 6: Determine the concentrations of each ion in the final solution.
To find the concentration of each ion, divide the number of moles of the ion by the total volume of the final solution:
Concentration of K+ ions = moles of K+ ions / total volume of the final solution.
Concentration of Ca2+ ions = moles of Ca2+ ions / total volume of the final solution.

By following these steps, you can calculate the concentrations of each ion present in the final solution.

There is not much to it.

how many moles of KCl? That give you the mole Cl, moles of K from that.

How many moles of CaCl2? That gives you themoles of Ca, and 2Cl ions.

Now add the Cl ions from the calcium chloride, and the KCl.
Concentration Cl=moles Cl/total volume and so on.