74. Sodium hydrogen carbonate is also known as baking soda. When this compound is heated, it decomposes to sodium carbonate, carbon dioxide, and water vapor. Write the balanced equation for this reaction. What volume of carbon dioxide gas at 77 degrees C and 756 mmHg will be produced from 26.8 g of sodium hyrodgen carbonate

2NaHCO3 >> Na2CO3 + H2O + CO2

NaHCO3>>Na2CO3+CO3+H2O

balance the equation, then proceed. I will be happy to check you work.

The balanced equation for the decomposition of sodium hydrogen carbonate, NaHCO3, is:

2 NaHCO3(s) → Na2CO3(s) + CO2(g) + H2O(g)

To find the volume of carbon dioxide gas produced, we can use the ideal gas law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

First, we need to calculate the number of moles of carbon dioxide produced. We can use the molar mass of NaHCO3 to convert the given mass of 26.8 g to moles.

Molar mass of NaHCO3:
Na = 22.99 g/mol
H = 1.01 g/mol
C = 12.01 g/mol
O = 16.00 g/mol

Molar mass of NaHCO3 = 22.99 + 1.01 + (12.01 + 3 * 16.00) = 84.01 g/mol

Number of moles = mass / molar mass = 26.8 g / 84.01 g/mol ≈ 0.3186 mol

Now, we can calculate the volume of carbon dioxide gas produced using the ideal gas law equation. But first, we need to convert the temperature from degrees Celsius to Kelvin:

Temperature in Kelvin = 77 + 273.15 = 350.15 K

Finally, we need to convert the pressure from mmHg to atm (since R is in atm):

Pressure in atm = 756 mmHg / 760 mmHg/atm ≈ 0.9958 atm

Now, we can substitute the values into the ideal gas law equation:

(0.9958 atm) x V = (0.3186 mol) x (0.0821 L·atm/K·mol) x (350.15 K)

Simplifying:

V = (0.3186 mol * 0.0821 L·atm/K·mol * 350.15 K) / 0.9958 atm

V ≈ 9.96 L

Therefore, approximately 9.96 liters of carbon dioxide gas will be produced from 26.8 g of sodium hydrogen carbonate at 77 degrees C and 756 mmHg.

To write the balanced equation for the decomposition of sodium hydrogen carbonate (baking soda), we need to know the formulas of the compounds involved:

Sodium hydrogen carbonate: NaHCO3
Sodium carbonate: Na2CO3
Carbon dioxide: CO2
Water vapor: H2O

The balanced equation for the reaction would be:

2 NaHCO3 → Na2CO3 + CO2 + H2O

Now, to calculate the volume of carbon dioxide gas produced, we need to use the ideal gas law equation:

PV = nRT

Where:
P = pressure of the gas (in this case, 756 mmHg)
V = volume of the gas (which we want to find)
n = number of moles of the gas
R = ideal gas constant (0.08206 L·atm/(mol·K))
T = temperature of the gas in Kelvin (77°C + 273.15 = 350.15 K)

To find the number of moles of carbon dioxide gas produced, we need to use its molar mass, which is 44.01 g/mol.

First, we need to convert the mass of sodium hydrogen carbonate to moles:

26.8 g NaHCO3 * (1 mol NaHCO3 / 84.01 g NaHCO3) = 0.3191 mol NaHCO3

Now, we can determine the number of moles of carbon dioxide produced. From the balanced equation, we know that 2 moles of NaHCO3 produce 1 mole of CO2:

0.3191 mol NaHCO3 * (1 mol CO2 / 2 mol NaHCO3) = 0.1596 mol CO2

Finally, we can calculate the volume of carbon dioxide gas using the ideal gas law equation:

V = (nRT) / P
V = (0.1596 mol CO2 * 0.08206 L·atm/(mol·K) * 350.15 K) / 756 mmHg

Note: We need to convert mmHg to atm by dividing by 760.

V = (0.1596 * 0.08206 * 350.15) / (756/760) L
V ≈ 0.0379 L

Therefore, approximately 0.0379 L of carbon dioxide gas will be produced.