Of 45 students 30 play badminton and 26 play tennis. Each student play either badminton or tennis,determine how many students play:(a)badminton only (b) tennis only
let the number who play both tennis and badminton be x
then
45 = 30+26-x
x = 11
badminton only ---> 30-11 = 19
tennis only ------> 26-11 = 15
Illustrate and confirm with a Venn diagram if you need to.
75 Student at the Certain School on the sport's they are interested in. The result are as follows; 40 play football , and 15 play both badminton and Football
Math work
Parang similar yung question sa module ng kapatid ko.
Wala po akong maintindihan sa question at sa mga answer niyo po.
To determine the number of students who play badminton only, we need to subtract the number of students who play both badminton and tennis from the total number of students who play badminton.
First, we find the number of students who play both badminton and tennis by finding the intersection of the two sets. We can calculate this by subtracting the number of students who play only badminton from the total number of students who play badminton:
30 (total badminton players) - x (students who play badminton only) = 26 (students who play both)
x = 30 - 26
x = 4
So, 4 students play both badminton and tennis.
To find the number of students who play badminton only, we subtract the students who play both from the total badminton players:
Students who play badminton only = Total badminton players - Students who play both
Students who play badminton only = 30 - 4
Students who play badminton only = 26
Therefore, there are 26 students who play badminton only.
Similarly, to find the number of students who play tennis only, we can use the same logic:
Students who play tennis only = Total tennis players - Students who play both
Students who play tennis only = 26 - 4
Students who play tennis only = 22
Hence, there are 26 students who play badminton only and 22 students who play tennis only.