# math

Inverse of h(x)=7-9cos(-(x+1)).

h^-1(x)=? show work please! Thanks.. also accidentally put this as an answer somewhere pls ignore that!

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1. h = 7-9cos(-(x+1))
9cos(-(x+1)) = 7-h
cos(-(x+1)) = (7-h)/9
-(x+1) = arccos((7-h)/9)
x+1 = -arccos((7-h)/9)
x = -1-arccos((7-h)/9)

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posted by Steve

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