Calculate the percentage composition of sulphuric acid if the atomic masses are H=1u, S=32u and 0=16u

The formula for sulphuric acid is H2SO4. So, first you add up the masses of all the components in the formula.

2 hydrogens = 1u * 2 = 2u
+
1 sulphur = 32u
+
4 oxygens = 16u * 4 = 64u
=
98u

98u is the mass of the compound, I'm not sure which element you are trying to find the percent composition of.

Once you have the element you are trying to find the percent composition of, you find that element's mass in the compound, divide it by the total (98u), and then multiply by 100 to get the percent.

For example, if you wanted the percent composition of hydrogen you would do:

2u/98u = 0.0204 * 100 = 2.0%

Hope this helps!

Note: When the question asks for percent composition of a compound, it means to find the percent of EACH element in the compound.

To calculate the percentage composition of sulphuric acid (H2SO4), you need to determine the molar mass of the compound first.

The molar mass of H2SO4 can be calculated as follows:
2(1u) + 1(32u) + 4(16u)
= 2u + 32u + 64u
= 98u

Now, to find the percentage composition of each element in the compound, divide the molar mass of each element by the molar mass of the compound and multiply by 100.

For hydrogen (H):
(2u / 98u) × 100 = 2.04%

For sulfur (S):
(32u / 98u) × 100 = 32.65%

For oxygen (O):
(64u / 98u) × 100 = 65.31%

Therefore, the percentage composition of sulphuric acid is:
- Hydrogen (H): 2.04%
- Sulfur (S): 32.65%
- Oxygen (O): 65.31%

To calculate the percentage composition of sulfuric acid (H₂SO₄), we need to determine the masses of each element present in the compound.

The molar mass of sulfuric acid (H₂SO₄) can be calculated by adding up the atomic masses of its elements:

H₂SO₄ = 2(H) + 1(S) + 4(O)
= 2(1u) + 1(32u) + 4(16u)
= 98u

Next, let's find the mass of sulfur (S) in sulfuric acid.

The percentage composition of sulfur in sulfuric acid is given by the ratio of the mass of sulfur to the molar mass of the compound, multiplied by 100%.

Mass of Sulfur (S) = Number of Sulfur Atoms (1) × Atomic Mass of Sulfur (32u)
= 1 × 32u
= 32u

Now, we can calculate the percentage composition of sulfur in sulfuric acid.

Percentage Composition of Sulfur = (Mass of Sulfur / Molar Mass of Sulfuric Acid) × 100%
= (32u / 98u) × 100%
≈ 32.65%

Therefore, the percentage composition of sulfur in sulfuric acid is approximately 32.65%.