What type of reaction is listed below? Prove that it is balanced by listing the number of elements on both side of the equation (reactants vs. products)? CH 3 COOH + NaHCO 3  NaCH 3 COO + H 2 CO 3

Question

What type of reaction is listed below? Prove that it is balanced by listing the number of elements on both side of the equation (reactants vs. products)? CH 3 COOH + NaHCO 3  NaCH 3 COO + H 2 CO 3

2. What type of reaction occurred with H 2 CO 3 from the above equation in the reaction below? CH 3 COOH + NaHCO 3  NaCH 3 COO + H 2 O + CO 2

Answer 1

2. It is a double displacement reaction. Some may call it an acid/base reaction, also, but I think you want the first one.

3. H2CO3 ==> H2O + CO2 is decomposition reaction.

Answer 2

To determine the type of reaction and prove that it is balanced, we need to count the number of elements on both sides of the equation.

1. Balancing the equation:

CH3COOH + NaHCO3 → NaCH3COO + H2CO3

To balance this equation, we need to make sure that the number of atoms of each element is the same on both sides.

On the left side, we have:

C: 2
H: 4
O: 3
Na: 1

On the right side, we have:

C: 2
H: 4
O: 5
Na: 1

We can see that the number of atoms of each element is not equal. To balance it, we can adjust the coefficients in front of each compound.

The balanced equation is:

2CH3COOH + 2NaHCO3 → 2NaCH3COO + H2CO3

Now, let's move on to question 2:

2. The reaction with H2CO3:

CH3COOH + NaHCO3 → NaCH3COO + H2O + CO2

From this equation, we can see that H2CO3 has decomposed into H2O and CO2. Therefore, the reaction that occurred with H2CO3 in the given equation is a decomposition reaction.