How much heat is needed to raise the temperature of 0.800kg ethyl alcohol from 15celsius to its boiling point at 78.3celsius?
To calculate the heat needed to raise the temperature of a substance, you can use the equation:
Q = mcΔT
where:
Q is the heat energy
m is the mass of the substance
c is the specific heat capacity of the substance
ΔT is the change in temperature
First, we need to calculate the change in temperature (ΔT):
ΔT = final temperature - initial temperature
= 78.3°C - 15°C
= 63.3°C
Ethyl alcohol's specific heat capacity is approximately 2.44 J/g°C. However, it's given that the mass of ethyl alcohol is 0.800 kg.
Therefore, we need to convert the mass of ethyl alcohol from kg to grams:
mass in grams = 0.800 kg * 1000 g/kg
= 800 g
Now we can substitute the values into the equation:
Q = mcΔT
= (800 g) * (2.44 J/g°C) * (63.3°C)
Calculating this equation:
Q ≈ 123,781.6 J
So, approximately 123,781.6 Joules of heat energy are required to raise the temperature of 0.800kg of ethyl alcohol from 15°C to its boiling point at 78.3°C.