if 24.25 mL of a standard M NaOH solution is required to neutralize 26.00 mL of H2SO4, what is the molarity of the acid solution?

You have to know the concentration of the NaOH solution.

Lets say that the NaOH solution is X M.

Number of millimoles of NAOH used is
24.25 x X

each millimole of NaOH neutralises half a millimole of H2SO4

so number of millimoles of H2SO4 is
24.25 x X x 0.5

if C (in mole per litre) is the concentration of H2SO4 then

26.00 x C = 24.24 x X x 0.5

so
C = 24.24 x X x 0.5/26.00

and you can find C when you know X

To find the molarity of the acid solution, we can use the equation:

Molarity (M) = (moles of solute) / (volume of solution in liters)

First, let’s calculate the moles of NaOH that reacted with H2SO4 using the given volumes and the equation balanced equation:

2 NaOH + H2SO4 -> Na2SO4 + 2 H2O

From the equation, we can see that 2 moles of NaOH react with 1 mole of H2SO4. Therefore, the moles of NaOH is two times the moles of H2SO4.

Let's calculate the moles of NaOH:
moles of NaOH = Molarity (M) x volume (L)

Given that the volume is 24.25 mL, we need to convert it to liters:
volume (L) = 24.25 mL / 1000 = 0.02425 L

Now we can calculate the moles of NaOH:
moles of NaOH = M x volume (L) = M x 0.02425 L

Since the moles of NaOH is twice the moles of H2SO4, we can divide the result by 2 to get the moles of H2SO4:
moles of H2SO4 = (M x 0.02425 L) / 2

Finally, we can calculate the molarity of the acid solution by rearranging the equation:

Molarity (M) = (moles of H2SO4) / (volume of solution in liters)

Given that the volume of the acid solution is 26.00 mL, we convert it to liters:
volume of solution (L) = 26.00 mL / 1000 = 0.02600 L

Now we can calculate the molarity of the acid solution:
Molarity (M) = (moles of H2SO4) / (0.02600 L)

By substituting the value of moles of H2SO4, we can determine the molarity.