A ferris wheel bucket travels around at 3.40 m/s. The radius of the ferris wheel is 39.8 m. What is the ferris wheel's angular velocity?
angvelociyt=3.4/radius
To find the ferris wheel's angular velocity, we can use the formula:
Angular velocity (ω) = velocity (v) / radius (r)
Given:
Velocity (v) = 3.40 m/s
Radius (r) = 39.8 m
Substitute the given values into the formula:
ω = 3.40 m/s / 39.8 m
Now let's calculate:
ω ≈ 0.0854 rad/s
Therefore, the ferris wheel's angular velocity is approximately 0.0854 rad/s.
To find the ferris wheel's angular velocity, we need to use the formula:
Angular Velocity (ω) = Linear Velocity (v) / Radius (r)
In this case, the linear velocity is given as 3.40 m/s, and the radius is 39.8 m. Substituting these values into the formula, we get:
Angular Velocity (ω) = 3.40 m/s / 39.8 m
Now, let's calculate the angular velocity:
ω = 3.40 m/s / 39.8 m
ω ≈ 0.0854 rad/s
Therefore, the ferris wheel's angular velocity is approximately 0.0854 rad/s.