Gunpowder contains 75%nitre and10% sulphur.find the amount of gunpowder which carries 9 kg nitre . what amount of gunpowder would contain 2.5kg sulphur
Set up the proportions:
9/x = 75/10
x/2.5 = 75/10
12kg and25kg
Pata nahi nt sure
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To find the amount of gunpowder that carries 9 kg of nitre, we need to figure out the total weight of the gunpowder. We know that 75% of the total weight is nitre, and 10% is sulphur.
Let's denote the total weight of the gunpowder as 'x'.
So, the weight of the nitre in the gunpowder would be 75% of x, which can be represented as 0.75x.
We are given that the weight of nitre is 9 kg, so we can set up an equation:
0.75x = 9
To find 'x', we can solve this equation:
x = 9 / 0.75
x = 12
Therefore, the amount of gunpowder that carries 9 kg of nitre is 12 kg.
Now, let's find the amount of gunpowder that would contain 2.5 kg of sulphur.
Similarly, we can set up an equation using the given information:
10% of the total weight of the gunpowder is sulphur, which can be represented as 0.10x.
We are given that the weight of sulphur is 2.5 kg, so we can set up the equation:
0.10x = 2.5
To find 'x', we can solve this equation:
x = 2.5 / 0.10
x = 25
Therefore, the amount of gunpowder that would contain 2.5 kg of sulphur is 25 kg.