You plan to remodel your dining room and you have chosen 1 foot by 1 foot ceramic tiles for the floor. The dining room is 6 feet by 5 inches long and 9 feet by 8 inches wide. How many tiles do you need to cover the dining room floor?
clearly 7 x 10 or 70 tiles.
Can you explain how I got that?
To calculate the number of tiles needed to cover the dining room floor, you first need to convert the dimensions of the room from feet to inches.
The length of the dining room is 6 feet and 5 inches, which can be converted to inches by multiplying 6 by 12 (since 1 foot equals 12 inches) and then adding the 5 inches. Therefore, the length of the dining room is (6 * 12) + 5 = 77 inches.
Similarly, the width of the dining room is 9 feet and 8 inches, which can be converted to inches by multiplying 9 by 12 and then adding the 8 inches. Therefore, the width of the dining room is (9 * 12) + 8 = 116 inches.
Now that we have the dimensions of the dining room in inches, we can calculate the total area in square inches. Multiply the length (77 inches) by the width (116 inches) to get 77 * 116 = 8,932 square inches.
Next, we need to determine the area covered by a single tile. Since each tile is 1 foot by 1 foot, which is equal to 12 inches by 12 inches, the area covered by one tile is 12 * 12 = 144 square inches.
Finally, divide the total area of the dining room by the area covered by each tile to find the number of tiles needed. Divide 8,932 square inches by 144 square inches to get 61.9722.
Since you cannot have a fraction of a tile, you will need to round up to the nearest whole number. Therefore, you will need 62 tiles to cover the dining room floor.