A car travelling along the road at 8 m/s.it accelerates at 1m/s square fir a distance of 18 km.how fast is it then travelling

To calculate the final velocity of a car after accelerating, you can use the equation:

v^2 = u^2 + 2as

Where:
- v is the final velocity
- u is the initial velocity
- a is the acceleration
- s is the distance traveled

First, let's convert the given distance from kilometers to meters:
18 km = 18,000 meters

Given information:
u = 8 m/s (initial velocity)
a = 1 m/s^2 (acceleration)
s = 18,000 m (distance traveled)

By substituting the values into the equation, we can solve for v:

v^2 = (8 m/s)^2 + 2 * 1 m/s^2 * 18,000 m

Simplifying this equation, we have:

v^2 = 64 m^2/s^2 + 2 * 1 m/s^2 * 18,000 m
v^2 = 64 m^2/s^2 + 36,000 m^2/s^2
v^2 = 36,064 m^2/s^2

To find v, we can take the square root of both sides of the equation:

v = √(36,064 m^2/s^2)

Calculating the square root, we find:

v ≈ 190.03 m/s

Therefore, the car is traveling at approximately 190.03 m/s after accelerating.