Given b=48, A=36 degrees find the remaining parts of the right triangle.
a=
a)51
b)35
c)66
d)29
and c=
a)35
b)26
c)82
d)59
This one I'm lost on!
a = b tan A = 34.8 (round it off to 35)
c = b/cos A = 59.3 (round it off to 59)
To find the remaining parts of the right triangle, we can use trigonometric ratios.
In this case, we are given that b = 48 and A = 36 degrees.
To find side a, we can use the tangent ratio (tan A). The tangent of an angle is equal to the ratio of the length of the opposite side to the length of the adjacent side. So, we have:
a = b * tan A
Substituting the given values, we get:
a = 48 * tan 36
Using a calculator, this evaluates to approximately 34.8. Rounded to the nearest whole number, side a is 35.
To find side c, we can use the cosine ratio (cos A). The cosine of an angle is equal to the ratio of the length of the adjacent side to the length of the hypotenuse. So, we have:
c = b / cos A
Substituting the given values, we get:
c = 48 / cos 36
Using a calculator, this evaluates to approximately 59.3. Rounded to the nearest whole number, side c is 59.
Therefore, the answers for side a and side c are:
a) 35
c) 59